dbase_pack
It took me a while to figure this out, so even though this is near-obsolete, maybe it will be useful to someone else.
I have a dBase file that contains a boolean value. I created a new row in the file with the boolean value at 0, and that worked without issues.
But then I tried to set that value to 1, and it did not work. I tried 1, "1", true - all without success.
Turns out that you need to use "Y" to set a boolean value to 1.
When you load the row later and output it using var_dump, the value will show as integer with the value 1.
dbase_replace_record
(PHP 4, PHP 5)
dbase_replace_record — Substitui um registro no banco de dados
Descrição
bool dbase_replace_record
( int
$dbase_identifier
, array $record
, int $record_number
)Substitui o registro no banco de dados com os dados indicados.
Parâmetros
-
dbase_identifier -
O identificador do banco de dados, retornado por dbase_open() ou dbase_create().
-
record -
Uma matriz indexada de dados. O número deve ser igual ao número de campo no banco de dados, se não dbase_add_record() irá falhar.
Nota:
Se você esta usando o valor de retorno de dbase_get_record() para este parâmetro, lembre-se de reiniciar o valor de deleted.
-
record_number -
Um inteiro que vai de 1 até o número de registros no banco de dados (como retornado por dbase_numrecords()).
Valor Retornado
Retorna TRUE em caso de sucesso ou FALSE em caso de falha.
Exemplos
Exemplo #1 Atualizando um registro no banco de dados
<?php
// open in read-write mode
$db = dbase_open('/tmp/test.dbf', 2);
if ($db) {
// gets the old row
$row = dbase_get_record_with_names($db, 1);
// remove the 'deleted' entry
unset($row['deleted']);
// Update the date field with the current timestamp
$row['date'] = date('Ymd');
// Replace the record
dbase_replace_record($db, $row, 1);
dbase_close($db);
}
?>
Veja Também
- dbase_add_record() - Adiciona um registro ao banco de dados
- dbase_delete_record() - Exclui um registro do banco de dados
add a note
User Contributed Notes
dbase_replace_record - [5 notes]
rlundp at lunds dot us ¶
4 months ago
xamkan at yahoo dot com ¶
2 years ago
// simply use 'dbase_get_record' instead of 'dbase_get_record_with_names', for 'dbase_replace_record', 'dbase_add_record', or 'dbase_delete_record', to work
<?php
// open in read-write mode
$db = dbase_open('/tmp/test.dbf', 2) or die("Error! Could not open dbase database file /tmp/test.dbf."); // 0=RO, 1=WO, 2=RW
// gets the old row
$row = dbase_get_record($db, 1);
// remove the 'deleted' entry from the array
unset($row['deleted']);
// Update the date field with the current timestamp
$row['date'] = date('Ymd');
// Replace the record
dbase_replace_record($db, $row, 1);
dbase_close($db);
?>
3Famous at gmail dot com ¶
5 years ago
Actually you have to change the read array from key based to element (numeric) based and everything works correctly!
<?php
$db = dbase_open( "yourfile.dbf", 2); // 0=RO, 1=WO, 2=RW
if ($db) {
$row = dbase_get_record_with_names($db, 1);
unset($row["deleted"]); // drop the field
// do whatever it is you want to the $row["elements"]
// then convert to numeric to store:
$rarr = array();
foreach ($row as $i=>$vl) $rarr[] = $vl;
dbase_replace_record($db, $rarr, 1);
dbase_close($db);
}
?>
That code actually works!
hassan at datakillarna dot se ¶
7 years ago
If you get "unexpected error", try to change the assoc array, $row, to an indexed array with array_values().
Example:
<?php
$row = array_values($row);
dbase_replace_record($db, $row, 1);
?>
The dbase_replace-function cannot handle an assoc array.
Hope this will save someone a headache! ;)
wysocki at wildworld dot net ¶
8 years ago
The dbase add and replace functions do NOT like to use the associative array.
<?php
//This gives "unspecified error" on replace and add:
$row = dbase_get_record_with_names($db, 1);
unset($row['deleted']);
dbase_replace_record($db, $row, 1);
dbase_add_record($db, $row);
//To further prove the point,
//The first add works, the second one fails:
$testrow1=array('one','2','three');
dbase_add_record($db,$testrow1);
$testrow2=array('FIELDA' => 'xxx','FIELDB' => '9','FIELDC' => 'yyyyy');
dbase_add_record($db,$testrow2);
?>