mysql_get_server_info
Please note that the information on warning count cannot be taken from the mysql_info() due to mysql bugs #41283 and #41285:
http://bugs.mysql.com/?id=41283
http://bugs.mysql.com/?id=41285
mysql_info
(PHP 4 >= 4.3.0, PHP 5)
mysql_info — Obtém informação sobre a consulta mais recente
Descrição
string mysql_info
([ resource
$link_identifier
] )Retorna informação detalhada sobre a última consulta.
Parâmetros
-
link_identifier -
The MySQL connection. If the link identifier is not specified, the last link opened by mysql_connect() is assumed. If no such link is found, it will try to create one as if mysql_connect() was called with no arguments. If no connection is found or established, an
E_WARNINGlevel error is generated.
Valor Retornado
Retorna informação sobre o comando em caso de sucesso, ou FALSE em
caso de falha. Veja o exemplo abaixo para quais comandos provêm informação,
e como o valor retornado se parecerá. Comandos não listados
irão retornar FALSE.
Exemplos
Exemplo #1 Comandos MySQL relevantes
Comandos que retornam valores de string. Os números são apenas para proposito de ilustração, os seus valores irão corresponder a consulta.
INSERT INTO ... SELECT ... String format: Records: 23 Duplicates: 0 Warnings: 0 INSERT INTO ... VALUES (...),(...),(...)... String format: Records: 37 Duplicates: 0 Warnings: 0 LOAD DATA INFILE ... String format: Records: 42 Deleted: 0 Skipped: 0 Warnings: 0 ALTER TABLE String format: Records: 60 Duplicates: 0 Warnings: 0 UPDATE String format: Rows matched: 65 Changed: 65 Warnings: 0
Notas
Nota:
mysql_info() retornará um valor diferente de
FALSEpara comandos INSERT ... VALUES apenas se multiplas listas de valores forem especificadas no comando.
Veja Também
- mysql_affected_rows() - Obtém o número de linhas atingidas na operação anterior do MySQL
- mysql_insert_id() - Obtém o ID gerado pela operação INSERT anterior
- mysql_stat() - Retorna o status atual do sistema
add a note
User Contributed Notes
mysql_info - [5 notes]
tomas at matfyz dot cz ¶
4 years ago
bdobrica at gmail dot com ¶
7 years ago
As a solution to the problem pointed in the post reffering to mysql_affected_rows() returning 0 when you are making an update query and the fields are not modified although the query is valid, i'm posting the following function. It is very simple and based on a previous post.
function mysql_modified_rows () {
$info_str = mysql_info();
$a_rows = mysql_affected_rows();
ereg("Rows matched: ([0-9]*)", $info_str, $r_matched);
return ($a_rows < 1)?($r_matched[1]?$r_matched[1]:0):$a_rows;
}
Hope you'll find it usefull.
info at granville dot nl ¶
7 years ago
Imade a quick conversion of eric's function just to count matched or affected rows from a query.
/**GD gdf_db_count_query_v1: returns the amount of rows matched or affected by the last query. Must be used immediately after the concerned query.
*/
function gdf_db_count_query($link = 'dbh') {
$info_str = mysql_info($$link);
if (ereg("Records: ([0-9]*)", $info_str, $count) == false) {
ereg("Rows matched: ([0-9]*)", $info_str, $count);
}
return $count;
}
eric at projectsatellite dot com ¶
9 years ago
I agree that this is a useful function to use when trying to check on whether an update query matched a particular row. I created a simple function that returns an associative array with the values delineated in the returned string.
function get_mysql_info($linkid = null){
$linkid? $strInfo = mysql_info($linkid) : $strInfo = mysql_info();
$return = array();
ereg("Records: ([0-9]*)", $strInfo, $records);
ereg("Duplicates: ([0-9]*)", $strInfo, $dupes);
ereg("Warnings: ([0-9]*)", $strInfo, $warnings);
ereg("Deleted: ([0-9]*)", $strInfo, $deleted);
ereg("Skipped: ([0-9]*)", $strInfo, $skipped);
ereg("Rows matched: ([0-9]*)", $strInfo, $rows_matched);
ereg("Changed: ([0-9]*)", $strInfo, $changed);
$return['records'] = $records[1];
$return['duplicates'] = $dupes[1];
$return['warnings'] = $warnings[1];
$return['deleted'] = $deleted[1];
$return['skipped'] = $skipped[1];
$return['rows_matched'] = $rows_matched[1];
$return['changed'] = $changed[1];
return $return;
}
After trying to update a row that may or may not exist, you can use the above function like so:
$vals = get_mysql_info($linkid);
if($vals['rows_matched'] == 0){
mysql_query("INSERT INTO table values('val1','val2', 'valetc')", $linkid);
}
carl at NOSPAMthep dot lu dot se ¶
10 years ago
This function can be used as a workaround for a misfeature of MySQL: on an UPDATE, rows that aren't updated _solely because they looked the same before_ will not be seen in mysql_affected_rows(). This causes problems when you want to use the result of the update to determine if there's need to do an INSERT. With MySQL you can do an INSERT IGNORE if there's no risk of if failing because of a duplicate key other than the one used in the UPDATE. However, if this isn't the case or you want a bit of RDBMS independence, there's no easy/pretty workaround. I think I'll resort to doing a SELECT to determine the primary key before doing the update/insert, as using the CVS version of PHP isn't an option for me.